sleep() errors

fdgfdgsdasfsdf · 2023-08-04T15:16:32+02:00

when i call sleep(500) it errors saying "attempt to yield across a C-call boundary" please help

Samir

Can you post an example that throws this error ?

fdgfdgsdasfsdf

Samir
local ui = require("ui") local window = ui.Window("",800,600) local button = ui.Button(window,"test",400,400,100,75) function button.onClick() sleep(500) end window:show() repeat ui.update() until not window.visible

Samir

Ok I will investigate this, thank you for this report 👍🏻

fdgfdgsdasfsdf

somehow it works when you compile the script to exe

fdgfdgsdasfsdf

fdgfdgsdasfsdf now it is the opposite, it works in .lua but doesnt in .exe

Samir

Yes, it's related to the bug with compiled scripts. I will provide a fix as soon as my vacation is over

Samir

For the moment consider that it's not possible to sleep() from an ui event. I will fix this for LuaRT 1.5.1

Dogi

fdgfdgsdasfsdf Ive got the same issue and it really bothers me since i haveto wait for some seconds until http requests succeeds so that i get my values

Samir

In this case you better use await() inside the event handler. Don't use sleep() to wait for another Task to terminate in an event handler.

You can use the Task.after property too.

Dogi

Samir Await helped, my bad, thank you

Samir

It's now fixed in LuaRT 1.5.1

Samir

fdgfdgsdasfsdf
For the same poster example ?
I will check this

fdgfdgsdasfsdf

Samir while true do print("test") sleep(500) end

it just closes

Samir

Thank you for the report, I have reproduced the bug.
I'am working on a fix

Samir

Update :
It's now fixed and will be available in next commit with a new LuaRT 1.5.2 bugfix release